Optimal. Leaf size=396 \[ \frac {2 x \left (d+e x^3\right )^{5/2} \left (667 a e^2-58 b d e+16 c d^2\right )}{11339 e^2}+\frac {30 d x \left (d+e x^3\right )^{3/2} \left (667 a e^2-58 b d e+16 c d^2\right )}{124729 e^2}+\frac {54 d^2 x \sqrt {d+e x^3} \left (667 a e^2-58 b d e+16 c d^2\right )}{124729 e^2}+\frac {54\ 3^{3/4} \sqrt {2+\sqrt {3}} d^3 \left (\sqrt [3]{d}+\sqrt [3]{e} x\right ) \sqrt {\frac {d^{2/3}-\sqrt [3]{d} \sqrt [3]{e} x+e^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{d}+\sqrt [3]{e} x\right )^2}} \left (667 a e^2-58 b d e+16 c d^2\right ) F\left (\sin ^{-1}\left (\frac {\sqrt [3]{e} x+\left (1-\sqrt {3}\right ) \sqrt [3]{d}}{\sqrt [3]{e} x+\left (1+\sqrt {3}\right ) \sqrt [3]{d}}\right )|-7-4 \sqrt {3}\right )}{124729 e^{7/3} \sqrt {\frac {\sqrt [3]{d} \left (\sqrt [3]{d}+\sqrt [3]{e} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{d}+\sqrt [3]{e} x\right )^2}} \sqrt {d+e x^3}}-\frac {2 x \left (d+e x^3\right )^{7/2} (8 c d-29 b e)}{667 e^2}+\frac {2 c x^4 \left (d+e x^3\right )^{7/2}}{29 e} \]
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Rubi [A] time = 0.42, antiderivative size = 396, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {1411, 388, 195, 218} \[ \frac {2 x \left (d+e x^3\right )^{5/2} \left (667 a e^2-58 b d e+16 c d^2\right )}{11339 e^2}+\frac {30 d x \left (d+e x^3\right )^{3/2} \left (667 a e^2-58 b d e+16 c d^2\right )}{124729 e^2}+\frac {54 d^2 x \sqrt {d+e x^3} \left (667 a e^2-58 b d e+16 c d^2\right )}{124729 e^2}+\frac {54\ 3^{3/4} \sqrt {2+\sqrt {3}} d^3 \left (\sqrt [3]{d}+\sqrt [3]{e} x\right ) \sqrt {\frac {d^{2/3}-\sqrt [3]{d} \sqrt [3]{e} x+e^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{d}+\sqrt [3]{e} x\right )^2}} \left (667 a e^2-58 b d e+16 c d^2\right ) F\left (\sin ^{-1}\left (\frac {\sqrt [3]{e} x+\left (1-\sqrt {3}\right ) \sqrt [3]{d}}{\sqrt [3]{e} x+\left (1+\sqrt {3}\right ) \sqrt [3]{d}}\right )|-7-4 \sqrt {3}\right )}{124729 e^{7/3} \sqrt {\frac {\sqrt [3]{d} \left (\sqrt [3]{d}+\sqrt [3]{e} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{d}+\sqrt [3]{e} x\right )^2}} \sqrt {d+e x^3}}-\frac {2 x \left (d+e x^3\right )^{7/2} (8 c d-29 b e)}{667 e^2}+\frac {2 c x^4 \left (d+e x^3\right )^{7/2}}{29 e} \]
Antiderivative was successfully verified.
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Rule 195
Rule 218
Rule 388
Rule 1411
Rubi steps
\begin {align*} \int \left (d+e x^3\right )^{5/2} \left (a+b x^3+c x^6\right ) \, dx &=\frac {2 c x^4 \left (d+e x^3\right )^{7/2}}{29 e}+\frac {2 \int \left (d+e x^3\right )^{5/2} \left (\frac {29 a e}{2}-\left (4 c d-\frac {29 b e}{2}\right ) x^3\right ) \, dx}{29 e}\\ &=-\frac {2 (8 c d-29 b e) x \left (d+e x^3\right )^{7/2}}{667 e^2}+\frac {2 c x^4 \left (d+e x^3\right )^{7/2}}{29 e}-\frac {1}{667} \left (-667 a-\frac {2 d (8 c d-29 b e)}{e^2}\right ) \int \left (d+e x^3\right )^{5/2} \, dx\\ &=\frac {2 \left (667 a+\frac {2 d (8 c d-29 b e)}{e^2}\right ) x \left (d+e x^3\right )^{5/2}}{11339}-\frac {2 (8 c d-29 b e) x \left (d+e x^3\right )^{7/2}}{667 e^2}+\frac {2 c x^4 \left (d+e x^3\right )^{7/2}}{29 e}+\frac {\left (15 d \left (667 a+\frac {2 d (8 c d-29 b e)}{e^2}\right )\right ) \int \left (d+e x^3\right )^{3/2} \, dx}{11339}\\ &=\frac {30 d \left (667 a+\frac {2 d (8 c d-29 b e)}{e^2}\right ) x \left (d+e x^3\right )^{3/2}}{124729}+\frac {2 \left (667 a+\frac {2 d (8 c d-29 b e)}{e^2}\right ) x \left (d+e x^3\right )^{5/2}}{11339}-\frac {2 (8 c d-29 b e) x \left (d+e x^3\right )^{7/2}}{667 e^2}+\frac {2 c x^4 \left (d+e x^3\right )^{7/2}}{29 e}+\frac {\left (135 d^2 \left (667 a+\frac {2 d (8 c d-29 b e)}{e^2}\right )\right ) \int \sqrt {d+e x^3} \, dx}{124729}\\ &=\frac {54 d^2 \left (667 a+\frac {2 d (8 c d-29 b e)}{e^2}\right ) x \sqrt {d+e x^3}}{124729}+\frac {30 d \left (667 a+\frac {2 d (8 c d-29 b e)}{e^2}\right ) x \left (d+e x^3\right )^{3/2}}{124729}+\frac {2 \left (667 a+\frac {2 d (8 c d-29 b e)}{e^2}\right ) x \left (d+e x^3\right )^{5/2}}{11339}-\frac {2 (8 c d-29 b e) x \left (d+e x^3\right )^{7/2}}{667 e^2}+\frac {2 c x^4 \left (d+e x^3\right )^{7/2}}{29 e}+\frac {\left (81 d^3 \left (667 a+\frac {2 d (8 c d-29 b e)}{e^2}\right )\right ) \int \frac {1}{\sqrt {d+e x^3}} \, dx}{124729}\\ &=\frac {54 d^2 \left (667 a+\frac {2 d (8 c d-29 b e)}{e^2}\right ) x \sqrt {d+e x^3}}{124729}+\frac {30 d \left (667 a+\frac {2 d (8 c d-29 b e)}{e^2}\right ) x \left (d+e x^3\right )^{3/2}}{124729}+\frac {2 \left (667 a+\frac {2 d (8 c d-29 b e)}{e^2}\right ) x \left (d+e x^3\right )^{5/2}}{11339}-\frac {2 (8 c d-29 b e) x \left (d+e x^3\right )^{7/2}}{667 e^2}+\frac {2 c x^4 \left (d+e x^3\right )^{7/2}}{29 e}+\frac {54\ 3^{3/4} \sqrt {2+\sqrt {3}} d^3 \left (16 c d^2-58 b d e+667 a e^2\right ) \left (\sqrt [3]{d}+\sqrt [3]{e} x\right ) \sqrt {\frac {d^{2/3}-\sqrt [3]{d} \sqrt [3]{e} x+e^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{d}+\sqrt [3]{e} x\right )^2}} F\left (\sin ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{d}+\sqrt [3]{e} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{d}+\sqrt [3]{e} x}\right )|-7-4 \sqrt {3}\right )}{124729 e^{7/3} \sqrt {\frac {\sqrt [3]{d} \left (\sqrt [3]{d}+\sqrt [3]{e} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{d}+\sqrt [3]{e} x\right )^2}} \sqrt {d+e x^3}}\\ \end {align*}
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Mathematica [C] time = 0.18, size = 103, normalized size = 0.26 \[ \frac {x \sqrt {d+e x^3} \left (\frac {\, _2F_1\left (-\frac {5}{2},\frac {1}{3};\frac {4}{3};-\frac {e x^3}{d}\right ) \left (29 d^2 e (23 a e-2 b d)+16 c d^4\right )}{\sqrt {\frac {e x^3}{d}+1}}-2 \left (d+e x^3\right )^3 \left (-29 b e+8 c d-23 c e x^3\right )\right )}{667 e^2} \]
Antiderivative was successfully verified.
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fricas [F] time = 1.08, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (c e^{2} x^{12} + {\left (2 \, c d e + b e^{2}\right )} x^{9} + {\left (c d^{2} + 2 \, b d e + a e^{2}\right )} x^{6} + {\left (b d^{2} + 2 \, a d e\right )} x^{3} + a d^{2}\right )} \sqrt {e x^{3} + d}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (c x^{6} + b x^{3} + a\right )} {\left (e x^{3} + d\right )}^{\frac {5}{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.26, size = 1070, normalized size = 2.70 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (c x^{6} + b x^{3} + a\right )} {\left (e x^{3} + d\right )}^{\frac {5}{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int {\left (e\,x^3+d\right )}^{5/2}\,\left (c\,x^6+b\,x^3+a\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 9.01, size = 400, normalized size = 1.01 \[ \frac {a d^{\frac {5}{2}} x \Gamma \left (\frac {1}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {1}{3} \\ \frac {4}{3} \end {matrix}\middle | {\frac {e x^{3} e^{i \pi }}{d}} \right )}}{3 \Gamma \left (\frac {4}{3}\right )} + \frac {2 a d^{\frac {3}{2}} e x^{4} \Gamma \left (\frac {4}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {4}{3} \\ \frac {7}{3} \end {matrix}\middle | {\frac {e x^{3} e^{i \pi }}{d}} \right )}}{3 \Gamma \left (\frac {7}{3}\right )} + \frac {a \sqrt {d} e^{2} x^{7} \Gamma \left (\frac {7}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {7}{3} \\ \frac {10}{3} \end {matrix}\middle | {\frac {e x^{3} e^{i \pi }}{d}} \right )}}{3 \Gamma \left (\frac {10}{3}\right )} + \frac {b d^{\frac {5}{2}} x^{4} \Gamma \left (\frac {4}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {4}{3} \\ \frac {7}{3} \end {matrix}\middle | {\frac {e x^{3} e^{i \pi }}{d}} \right )}}{3 \Gamma \left (\frac {7}{3}\right )} + \frac {2 b d^{\frac {3}{2}} e x^{7} \Gamma \left (\frac {7}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {7}{3} \\ \frac {10}{3} \end {matrix}\middle | {\frac {e x^{3} e^{i \pi }}{d}} \right )}}{3 \Gamma \left (\frac {10}{3}\right )} + \frac {b \sqrt {d} e^{2} x^{10} \Gamma \left (\frac {10}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {10}{3} \\ \frac {13}{3} \end {matrix}\middle | {\frac {e x^{3} e^{i \pi }}{d}} \right )}}{3 \Gamma \left (\frac {13}{3}\right )} + \frac {c d^{\frac {5}{2}} x^{7} \Gamma \left (\frac {7}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {7}{3} \\ \frac {10}{3} \end {matrix}\middle | {\frac {e x^{3} e^{i \pi }}{d}} \right )}}{3 \Gamma \left (\frac {10}{3}\right )} + \frac {2 c d^{\frac {3}{2}} e x^{10} \Gamma \left (\frac {10}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {10}{3} \\ \frac {13}{3} \end {matrix}\middle | {\frac {e x^{3} e^{i \pi }}{d}} \right )}}{3 \Gamma \left (\frac {13}{3}\right )} + \frac {c \sqrt {d} e^{2} x^{13} \Gamma \left (\frac {13}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {13}{3} \\ \frac {16}{3} \end {matrix}\middle | {\frac {e x^{3} e^{i \pi }}{d}} \right )}}{3 \Gamma \left (\frac {16}{3}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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